F(x)=3-5x+4x^2

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Solution for F(x)=3-5x+4x^2 equation: 



(F)=3-5F+4F^2

We move all terms to the left:

(F)-(3-5F+4F^2)=0

We get rid of parentheses

-4F^2+5F+F-3=0

We add all the numbers together, and all the variables

-4F^2+6F-3=0

a = -4; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-4)·(-3)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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